Friday, 26 June 2015

LIGHT OJ – 1000 ( Greetings from LightOJ )_Solution

//Tanzila Islam

//Southeast University

//mail : tanzilamohita@gmail.com


#include <iostream>

using namespace std;


int main() {

    int t;


    cin >> t;


    for (int i = 1 ; i <= t; i++) {

        int n1, n2, n3;

        cin >> n1 >> n2;

        n3 = n1 + n2;

        cout << "Case " << i << ": " << n3 << endl;

     }


     return 0;


 }

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